Math, asked by shakeelabegum26597, 1 month ago

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Answered by viyA567
0

if AD perpendicular to BC then d is themid point of BC;BD=DC=BC/2=A/2 units

triangle ADC is a right angled triangle.

Then by Pythagoras theorem,

AD square=AC square- DC square=a square-(a) square/4

4a square-a square/4=3a square/4 =AD =√3 a square/4=√3/2 a units

hence√3/2 a proved

Answered by mousami2007
0

Answer:

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