plz slovve by substitution method
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i) √2x + √3y = 0 .....(i)
√3x - √8y = 0 ......(ii)
Let us consider the Equation (ii)
√3x - √8y = 0
x = √8y/√3 ......(iii)
Put the value of x = √8y/√3 in Equation (i),
√2 x √8y/√3 + √3y = 0
√16y + 3y = 0
y(√16 + 3) = 0
y = 0 , x = 0
ii) 3x/2 - 5y/3 = -2 .....(i)
x/3 + y/2 = 13/6 ......(ii)
Let us consider the Equation (ii)
x/3 + y/2 = 13/6
x/3 = 13/6 - y/2
x = 3(13 - 3y)/6
x = (13 - 3y)/2 ......(iii)
Put the value of x = (13 - 3y)/2 in Equation (i),
4 + y + y = 14
2y = 14 - 4
2y = 10
y = 10/2
y = 5
Put the value of y = 5 in equation (i)
x + 5 = 14
x = 14 - 5
x = 9, y = 5
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