Plz solve 11 12 13 questions
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in Q11.all angles are equal
so ,3x=180
x=180/3
x=60
in Q12.y=80 (vertically opposite angles)
y+x+50=180
x=180-(80+50)
=180-130=50
inQ13.,x=50( corresponding angles)
x+y=127(exterior angle of a triangle is the sum of two interior angles)
y=127-50=77
so ,3x=180
x=180/3
x=60
in Q12.y=80 (vertically opposite angles)
y+x+50=180
x=180-(80+50)
=180-130=50
inQ13.,x=50( corresponding angles)
x+y=127(exterior angle of a triangle is the sum of two interior angles)
y=127-50=77
khushi7020:
Thank u so much
Answered by
0
q11
since it is an equilateral traiangle
q12
x=
y+50+x=180
80+50+x=180
x=50
q13
50 +y=127. alternate angles
y=77
x=
x+y+53=180. linear pair
x+77+53=180
x=50
since it is an equilateral traiangle
q12
x=
y+50+x=180
80+50+x=180
x=50
q13
50 +y=127. alternate angles
y=77
x=
x+y+53=180. linear pair
x+77+53=180
x=50
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