plz solve 13 and 14 and 15
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(14)...(5/7)^3/4 × (7/5)^2×3/8
;(5/7)^3/4 × (7/5)^3/4
;{5/7 ×7/5)^3/4
;1^3/4=1
(13)..1-√2/1+√2 × 1-√2/1-√2=-3+m√2
;(1-√2)^2/1^2-(√2)^2=-3+m√2
;1+2-2√2/1-2=-3+m√2
;3-2√2/-1=-3+m√2
;-3+2√2+3=m√2
;2√2/√2=m
;m=2
is your answer
;(5/7)^3/4 × (7/5)^3/4
;{5/7 ×7/5)^3/4
;1^3/4=1
(13)..1-√2/1+√2 × 1-√2/1-√2=-3+m√2
;(1-√2)^2/1^2-(√2)^2=-3+m√2
;1+2-2√2/1-2=-3+m√2
;3-2√2/-1=-3+m√2
;-3+2√2+3=m√2
;2√2/√2=m
;m=2
is your answer
TheGENIUSBoy:
Question no. 13 . m=2
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