plz solve 17th sum plzzzz
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Answer:
Step-by-step explanation:
if a+b+c=0
we need to show that a3+b3+c3=3abc
proof
a3+b3+c3-3abc={a+b+c] [a2+b2+c2-ab-bc-ca}
{since a+b+c=0}
therefore a3+b3+c3=3abc
i hope this answer helps u
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