Math, asked by trisha10433, 10 months ago

plz solve..................

Attachments:

Answers

Answered by devilgamer123sk
0

Answer:

cube 3 subtract 4² is the answer dear

Answered by waqarsd
1

Answer:

b) exactly one irrational solution.

\large{\bold{x=(\frac{5\sqrt{2}}{4})^\frac{5}{4}}}

Step-by-step explanation:

Given\\\\x^{\frac{3}{4}log_2x^2+log_2x-\frac{5}{4}}=\sqrt{2}\\\\x^{\frac{3}{4}\times 2log_2x+log_2x-\frac{5}{4}}=\sqrt{2}\\\\x^{\frac{3}{2}log_2x+log_2x-\frac{5}{4}}=\sqrt{2}\\\\x^{\frac{5}{2}log_2x-\frac{5}{4}}=\sqrt{2}\\\\x^{log_2x^\frac{5}{2}}.x^{-\frac{5}{4}}=\sqrt{2}\\\\\frac{5}{2}.x^{-\frac{5}{4}}=\sqrt{2}\\\\x^{-\frac{5}{4}}=\frac{2\sqrt{2}}{5}\\\\x=(\frac{5}{2\sqrt{2}})^\frac{5}{4}\\\\x=(\frac{5\sqrt{2}}{4})^\frac{5}{4}

HOPE IT HELPS

Similar questions