plz solve
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The identity suitable here is
(a+b)^3 = a^3 + b^3 + 3 ab(a+b)
Here a = 100
b = 5
(100+5)^3 = (100)^3 + 5^3 + 3×500(105)
= 1000000+125+1500×105
= 180,000,00,000
(a+b)^3 = a^3 + b^3 + 3 ab(a+b)
Here a = 100
b = 5
(100+5)^3 = (100)^3 + 5^3 + 3×500(105)
= 1000000+125+1500×105
= 180,000,00,000
prince293:
tq vidhi
pleasure
vidhi one . more question
is there
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