plz solve. ................
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just keep in mind...
if Lim X tends to-0
THEn sinx/x=1
![(ax + x \cos(x)) \div (b \sin(x) ) \\ (ax + x \cos(x) ) \div (xbsinx \div x) \\ = x(a + \cos(x) ) \div (xb) \\ = (a + \cos(x) ) \div b \\ at \: x = 0 \\ = (a + 1) \div b (ax + x \cos(x)) \div (b \sin(x) ) \\ (ax + x \cos(x) ) \div (xbsinx \div x) \\ = x(a + \cos(x) ) \div (xb) \\ = (a + \cos(x) ) \div b \\ at \: x = 0 \\ = (a + 1) \div b](https://tex.z-dn.net/?f=%28ax+%2B+x+%5Ccos%28x%29%29++%5Cdiv+%28b+%5Csin%28x%29+%29+%5C%5C+%28ax+%2B+x+%5Ccos%28x%29+%29+%5Cdiv+%28xbsinx+%5Cdiv+x%29+%5C%5C++%3D+x%28a+%2B++%5Ccos%28x%29+%29+%5Cdiv+%28xb%29+%5C%5C++%3D+%28a+%2B++%5Ccos%28x%29+%29+%5Cdiv+b+%5C%5C+at+%5C%3A+x+%3D+0+%5C%5C+%3D++%28a+%2B+1%29+%5Cdiv+b)
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if Lim X tends to-0
THEn sinx/x=1
mark as brainliest if helped
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