Question

plz solve 2nd and 4th sum

Answer 1

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Here is your answer
2.
Area = 180 sq cm
Base = 15 cm
Let the altitude = x cm
As we know the formula

Area of triangle = 1/2 × base × Altitude
$180 \: = \frac{1}{2} \times 15 \times x \\ x = \frac{180 \times 2}{15} \\ x = \frac{360}{15} \\ x = 24 \: cm$
So altitude is 24 cm

4. In ∆ ABC
Base AB = 5 cm
Altitude CE = 6 cm

So
Area of triangle is
$= \frac{1}{2} \times 5 \times 6 \\ = 15cm {}^{2}$
Now
Base AC. = 4.8 cm
Altitude. BD = x cm
Area = 15sq cm

Area of triangle = 1/2 × base× altitude
$15 = \frac{1}{2} \times 4.8 \times x \\ x = \frac{15 \times 2}{4.8} \\ x =6.25 \: cm$
So Altitude BD IS = 6.25 cm

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