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3 cells are connected in parallel with their like poles connected together with wire of negligible resistance. The emf of the cells are 2V ,3V, 4V respectively and their internal resistance are 1 ohm , 2 ohm and 3 ohm respectively. Find the current through each branch .
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Let the current coming out of Cell 4V be i1.
Let the current coming out of Cell 3 V be i2.
Then the current going into cell 2V is = i1+i2.
The potential available outside the cells = same
So 4 - 3 i1 = 3 - 2 i2 = 2 + i1
=> 3 i1 - 2 i2 = 1
=> i1 + 2 i2 = 1
Solving them: i1 = 0.50 Amp
i2 = 0.25 A
Current through the 2 V cell is 0.75 A
Let the current coming out of Cell 3 V be i2.
Then the current going into cell 2V is = i1+i2.
The potential available outside the cells = same
So 4 - 3 i1 = 3 - 2 i2 = 2 + i1
=> 3 i1 - 2 i2 = 1
=> i1 + 2 i2 = 1
Solving them: i1 = 0.50 Amp
i2 = 0.25 A
Current through the 2 V cell is 0.75 A
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