plz solve 3rd one.......
value of p
...
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2
Step-by-step explanation:
Now the equation is x^2+5x+p=p(x)
Alpha and beta are zeros or solutions of this equation
Now as we know alpha+beta=-b/a and alpha×beta=c/a(in equation ax^2+bx+c=0)
Now a=2,b=5,c=p alpha^2+beta^2=(alpha+beta)^2-2alpha×beta
Now alpha^2+beta^2+alphabeta=21/4
Which means
(-5/2)^2-p+p/2=21/4
25/4-p/2=21/4
P/2=25-21/4
P/2=1
P=2
neha7254:
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