plz solve 3rd question picture attached
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in ∆abc &∆cda
ab=cd
bc=ad
angle b=angle d
since ABCD is a parellelogram.
∆abc =~ ∆cda(SAS)
ab=cd
bc=ad
angle b=angle d
since ABCD is a parellelogram.
∆abc =~ ∆cda(SAS)
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