Question

plz solve
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Answer 1

$\frac{1}{1 + x + \frac{1}{y} } + \frac{1}{1 + y + \frac{1}{z} } + \frac{1}{1 + z + \frac{1}{x} } \\ since \: \: xyz = 1 \\ put \: \frac{1}{y} = xz \: in \: 1st \: term \: \: and \\ y = \frac{1}{xz} \: in \: 2nd \: term$
$\frac{1}{1 + x + xz} + \frac{1}{1 + \frac{1}{xz} + \frac{1}{z} } + \frac{1}{1 + z + \frac{1}{x} }$
$\frac{1}{1 + x + xz} + \frac{xz}{xz + 1 + x} + \frac{x}{x + xz + 1} \\ = \frac{1 + xz + x}{1 + x + xz} = 1$

Answer 2

hi Aksh.................