Question

plz solve 5 nd 6 question​

Answer 1

Answer:

Step-by-step explanation:

5.  x + 5 > 4x - 10

Adding 10 to both sides : -

= > x + 5 + 10 > 4x - 10 + 10

= > x + 15 > 4x

Adding - x to both sides : -

= > x + 15 - x > 4x - x

= > 15 > 3x

Divide both sides by 3 : -

= > 15 / 3 > 3x / 3

= > 5 > x

Therefore the solution set is { ..... 0 , 1 , 2 , 3 , 4 }.

$6.\quad\dfrac{3x-2}{5}\leq \dfrac{4x-3}{2}$

Multiply both sides by 10 : -

$= > (3x-2)2\leq 5(4x-3)\\\\=>6x-4\leq 20x-15\\\\=>15-4\leq 20x-6x\\\\=>11\leq 14x\\\\=>11/14\leq x$

Therefore the solution set is { 1 , 2 , 3 , 4 ..... }

Answer 2

Q5.

x-4x> -10-5

-3x> -15

x<5

Q6.

$2(3x - 2) \leqslant 5(4x - 3) \\ \\ 6x - 4 \leqslant 20x - 15 \\ \\ 6x - 20x \leqslant - 15 + 4 \\ \\ - 14x \leqslant - 11 \\ \\ x \geqslant \frac{11}{14}$

hope it will help