Question

plz solve 6th question

Answer 1

Area of a Δ is (1/2)*base*height.

So with reference to the figure,

     Ar(ΔAPD)=(1/2)*x*DP...................(1)

    Ar(ΔBPC)=(1/2)*y*BP..................(2)

Since height for ΔAPB is x and for ΔCPD is y

So   Ar(ΔAPB)=(1/2)*x*BP...................(3)

     Ar(ΔAPD)=(1/2)*y*DP..................(4)

Thus from (1),(2),(3) and (4),

Ar(ΔAPD)*Ar(ΔBPC)=Ar(ΔAPB)*Ar(ΔAPD)