Question

plz solve 9 10th 11 sums

Answer 1

$\large \tt AHOY!! \:$


9. given :-

side of the rhombus = 13cm

length of one of it's diagonal = 24cm

here we have to find the area of the Rhombus. and the formula to find it's area is '1/2 × d1 × d2'

so first of all, let's find d2 (length of another diagonal)

by Pythagoras theorem we get,

=> side² (hypotenuse) = (d1/2)² + (d2/2)²

=> 13² = 12² + (d2/2)²

=> 169 = 144 + (d2/2)²

=> 169 - 144 = (d2/2)²

=> 25 = (d2/2)²

=> √25 = d2/2

=> 5 = d2

=> 5 × 2 = d2

=> d2 = 10cm

the length of the other diagonal of the rhombus is 10cm.

therefore it's area = 1/2 × d1 × d2

= 1/2 × 24 × 10

= 12 × 10

= 120cm²

10. given :-

side of the Rhombus = 20cm

length of one of the diagonal = 24cm

by using same method as we used above, we will first find the length of other diagonal and then area of the Rhombus.

by Pythagoras theorem :-

=> side² = (d1/2)² + (d2/2)²

=> 20² = 12² + (d2/2)²

=> 400 = 144 + (d2/2)²

=> 400 - 144 = (d2/2)²

=> 256 = (d2/2)²

=> √256 = d2/2

=> 16 = d2/2

=> 16 × 2 = d2

=> d2 = 32cm

therefore the length of the other diagonal is 32cm.

hence, it's area = 1/2 × d1 × d2

= 1/2 × 24 × 32

= 12 × 32

= 384cm²

11. ATQ, the area of Rhombus and parallelogram is equal.

given :-

length of the diagonals of the rhombus is 18 and 15cm.

area of the Rhombus = 1/2 × d1 × d2

= 1/2 × 18 × 15

= 9 × 15

= 135cm²

therefore area of the parallelogram = 135cm² (since the area of both are equal)

$\large \tt HOPE \: THIS \: HELPS!!$

Answer 2

Answer

Hope it may be HELPFUL