Question

plz solve ,..................... .............​

Answer 1

answere:- new vapour pressure is 34.29

and decrease in V.P=35–34.29

=0.71

formula used (P–P¹)/P¹=X2

P= vapour pressure of pure solvent

P¹=vqpour pressure of solution

X2=mole fraction of solute

no. of mole of glucose=20/180=0.11

no. of mole of sucrose=34.2/342=0.1

no. of moles of water=180/18=10

Total no. of moles=10+0.11+0.1=10.21

mole fraction of solvent

=(0.11/10.21)+(0.1/10.21)

=0.0205

let x be new V.P

using above formula

(35-x)/x=0.0205

→35-x=0.0205x

→x=35/1.0205

→x=34.29