plz solve aaaaaaaàaaaaaaaaaa
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wait Mr hanzo wait for attachment
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Let us write the given pair of equation as-:
21(1/x)+47(1/y)=110
47(1/x)+21(1/x)=162
These eq. are not in the form of ax+by+c=0
However if we substitute 1/x=p and 1/y=q in the given eq
21p+47q=110......(1)
47p+21q=162....(2)
p=110-47q/21 ....(3) {from eq 1}
substituting the value of p in eq 2
47(110-47q/21)+21q=162
5170-2209q+441q=3402
-1768q=3402-5170
-1768q=-1768
q=-1768/-1768
q=1
substituting the value of q in eq 3
p=110-47(1)/21
p=63/21
p=3
p=1/x
3=1/x
x=1/3
q=1/y
1=1/y
y=1
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