Plz solve above question
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3 mark question ?
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Answered by
2
total no of packets containing toy cars = n = 600
no of packets which does not contain any faulty cars = m = 360
therefore the probability that a randomly selected pack does not contain any faulty toy car will be
= m/n
=360/600
=0.6
no of packets which does not contain any faulty cars = m = 360
therefore the probability that a randomly selected pack does not contain any faulty toy car will be
= m/n
=360/600
=0.6
Answered by
2
Total number of packets = 600
Number of packets that don't have any faulty car = 360
Probability = No. of packets that don't have faulty cars/Total number of packets
= 360/600 = 3/5
Number of packets that don't have any faulty car = 360
Probability = No. of packets that don't have faulty cars/Total number of packets
= 360/600 = 3/5
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