Question

plz solve above question..

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Answer 1

Answer:

Distance will be 30/40 i.e. 3/4 and i.e. 0.75 cm

Answer 2

$\huge \mathfrak \green{ÄÑẞWËR}$

Explanation:

$Here, \: f = -30 cm \: , \: u = -40 cm$

$Image \: distance \: can \: be \: calculated \: as \: follows :$

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$

$\frac{1}{v} - \frac{1}{40} = - \frac{1}{30}$

$\frac{1}{v} = - \frac{1}{30} + \frac{1}{40}$

$= \frac{ - 4 + 3}{120} = - \frac{1}{120}$

$v = - 120cm$

$image \: distance \: (v) \: 120cm$

$\red{Find the magnification as well.}$

$Magnification \: can \: be \: calculated \: as \: follows :$

$m = \frac{v}{u} = \frac{ - 120}{ - 40} = 3$

The positive sign with magnification show that image is real.

$\pink{i \: hope \: it \: helpfull \: for \: you}$