Question

plz solve above question...

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Answer 1

$\huge\sf\fbox\red{hope this helps you}$

Answer 2

$\huge \mathfrak \blue{ÆÑẞWËR}$

Step-by-step explanation:

$the \: two \: zeroes \: of \: the \: polynomial \: is \: 2 + \sqrt{3} \: . \: 2 - \sqrt{3}$

$therefore \: (x - 2 + \sqrt{3})(x - 2 - \sqrt{3}) = {x}^{2} + 4 - 4x - 3$

$= {x}^{2} - 4x + 1 \: is \: a \: factor \: of \: the \: given \: polynomial$$using \: division \: algrithm \: we \: get$

${x}^{4} - 6 {x}^{3} - 26 {x}^{2} + 138x - 35 = ( {x}^{2} - 4x + )( {x}^{2} - 2x - 35)$

$so\:({x}^{2}-2x-35)is \: also \: a \: factor \: of \: given \: polynomial$

$= {x}^{2} - 2x - 35 = {x}^{2} - 7x + 5x - 35$

$= x(x7) + 5(x - 7)$

$= (x - 7) \: \: \: (x + 5)$

$\pink{i \: hope \: it \: helpfull \: for \: you}$