Chemistry, asked by Anonymous, 1 year ago

Plz solve all these it is for 50 marks plz
Here in this question no. 6-10 all thes question 6 to 10 plz

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Anonymous: di , wait I will solve and send it within 1-2 hrs ... before 3 pm
Anonymous: di , wait I will solve and send it within 1-2 hrs ... before 3 pm
aryapatil84: Hey mate I have already solved it
Anonymous: Thanks u both

Answers

Answered by aryapatil84
3

Answer:Hey dear please mark it brainleast morever I am expert in chemistry and physics if u need help in these subject please message me.Your ans is given below in pic

Explanation:

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Anonymous: Well volume coming is 93.0.... Something l ,
Anonymous: **We can use that 1 mole of gas occupies 22.4 l isn't it ?
aryapatil84: Yes
Anonymous: ••Sory my mistake....↑↑ ignore above
Anonymous: Thanks
aryapatil84: Welcome
Answered by Anonymous
6

Answer :-

** Please consider attached for solution.

Question No. 6 :-

▪️Volume = 426.2 cm³ or 0.4262 lite

Question No. 7 :-

\bold{No. \:of \:electrons = 4.215 \times 10^{23}}

Question No. 8 :-

→ (a) = 4 moles

→(b) = 2 moles

→(c) = 10 moles

\bold{ d = \dfrac{1}{3} \: moles}

→ (e) = 0.1975 moles

→ (f) = 5.417 moles

Question No. 9 :-

\bold{a = 17.93 \times 10^{-23}\: grams}

(b) = 28 grams

(c) = 100 grams

(d) = 0.19926 grams

**Ignore Solution attached for 9.(d) it's wrong as I have took mass of Carbon = 6

◾Solution for 9.(d)

 10^{22} \: atoms\: of\: Carbon

▪️No. of moles = \dfrac{10^{22}}{6.022 \times 10^{23}}

 = \dfrac{1}{6.022\times 10}

▪️Now Mass

 = \dfrac{1}{6.022\times 10}\times 12

 = \dfrac{1.2}{6.022}

= 0.19926 grams

Question No. 10 :-

(i) = 11.2 liters

(ii) = 33.6 liters

(iii) = 37.2 liters

(iv) = 2.82074 liters

Solution for 10.(iv)

3.4 g of Ammonia(NH_3)

Molar mass of Ammonia = 27

No of moles  = \dfrac{3.4}{27}

volume of the gas = \dfrac{3.4 \times 22.4}{27}

Volume of gas = 2.82074 liters

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