Question

plz solve all these questions.
no fake answers plz.
best answers will mark as brainlist answer.
plz answer the question by marking the question number.


plz help me.

Answer 1

☆■■■ Hello Friend ■■■☆
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SECTION B

7) 12x + 17x + 25x = 540
54x = 540
x = 540/54 = 10 cm
Sides = 17×10 = 170cm
12×10 = 120 cm, 25 ×10 = 250 cm

$area \: = \sqrt{s(s - a)(s - b)(s - c)} \\ s = \frac{540}{2} = 270 \\ \sqrt{270(270 - 120)(270 - 17)(270 - 250)} \\ \sqrt{270 \times 150 \times 100 \times 20} \\ \sqrt{3 \times 3 \times 3 \times 2 \times 5 \times 2 \times 3 \times 3 \times 5 \times 2 \times 2 \times 5 \times 5 \times 2 \times 2 \times 5} \\ 2 \times 2 \times 2 \times 3 \times 3 \times 1.74 \times 5 \times 5 \times 2.23 \\ = 7003.5 \: {cm}^{2}$

8) /_ BXM = /_XMA = 135°
/_ XMA + XMB = 180°
/_ XMB = 180° - 135°
/_ XMB = 45°

/_ MYR = /_BMY = 40°
45° + 40° = 95°

/_ BMY = 95°

9) (i) In triangle APB and CQD WE HAVE
/_APB = CQD ( 90° )
AB = CD
/_ABP = /_CDQ ( Alternate Angle )

Hence both triangles are congruent.
Then, AP = CQ ( c.p.c.t )

Hey friend, its kind request that don't post so many question which cause pain in eyes.

Hope u understand☺!✌