Question

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Answer 1

Question

Find the value of x, when in the A.P. given below

2 + 6 + 10 + ..... + x = 1800

Answer

118

Explanation

Let x be the nth term of the given A.P.

Then, it shows that sum of n terms of A.P. = 1800

Apply the formula of sum of A.P.

$\sf S_n = \frac{n}{2}(2a + (n - 1)d)$

Here we have, Sn = 1800

a = 2

d = 4

Hence,

$\sf 1800 = \frac{n}{2}(2\times 2 + (n - 1)4)$

$\sf 1800 = \frac{n}{2}(4 + 4n - 4)$

$\sf 1800 = \frac{4n^2}{2}$

→ 2n² = 1800

→ n² = 900

→ n = ±30

We know that n is a natural numbers hence we will reject negative value

→ n = 30

We knew that x is nth term of the A.P.

→ x is the 30th term of the A.P.

Apply the general term formula of A.P. to find the value of

$\sf a_n = a + (n - 1)d$

$\sf x = 2 + (30 - 1)4$

$\sf x = 2 + 29 \times 4$

$\sf x = 118$

Answer 2

Answer:

118 is the correct answer plz follow and feedback