Question

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Answer 1

Answer:

in triangle PRT,

angle TRP+ angle RPT+ angle PTR= 180°

40°+95° + angle PTR= 180°

135°+ angle PTR= 180°

angle PTR= 180‐135

angle PTR= 45°

angle PTR= 45°= angle STQ (opposite angle)

in triangle STQ,

angle STQ+ angle QST+ angle SQT= 180°

45°+ angle QST+ 75°= 180°

120°+ angle QST= 180°

angle QST= 180-120

angle QST= 60°

HOPE IT HELPS YOU

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Answer 2

Answer:

Step-by-step explanation:

In PRT

By angle sum property of triangle

∠PRT+∠RPT+∠PTR=180°

⇒90  +45  +∠PTR = 180°

⇒135+∠PTR=180°

 ⇒∠PTR=180 −135

⇒∠PTR = 45°

Also,

∠STQ=∠PTR

∠STQ=45  (vertically opposite angles)

In ΔSQT

By angle sum property of triangle  

∠SQT+∠STQ+∠TSQ = 180°  

∠SQT+75°  + 45°  = 180°  

∠SQT+120°  = 180°

∠SQT=180° − 120°  

∠SQT=60  

HOPE IT HELPED....