Question

plz solve and send................​

Answer 1

Step-by-step explanation:

$(1 + { \tan( \alpha ) }^{2}) = { \sec( \alpha ) }^{2} \\ lhs \\ \frac{ { \sec( \alpha ) }^{2} \times \cot( \alpha ) }{ { \csc( \alpha ) }^{2} } \\ = \frac{ { \sin( \alpha ) }^{2} \times \cos( \alpha ) }{ { \cos( \alpha ) }^{2} \times \sin( \alpha ) } \\ = \frac{ \cos( \alpha ) }{ \sin( \alpha ) } \\ = \tan( \alpha )$

hence proved ...plz mark brainliest