Math, asked by n5536015, 6 months ago

plz solve and send the solution for this question

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Answers

Answered by yashupadhyay100
1

Answer:

sin27

0

−cos27

0

⇒sin27

0

−cos(90

0

−63

0

)

⇒sin27

0

−sin63

0

⇒2cos(

2

27

0

+63

0

)sin(

2

27

0

−63

0

)

⇒2cos45

0

sin(−36

0

)

⇒2×

2

1

×−[

4

10−2

5

]

⇒−

2

1

×

2

(

2

5−

5

)

⇒−

2

5−

5

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