Math, asked by deepalijain2003, 1 year ago

plz solve anyone

find a ND b

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Answered by pal69
1

[(1-i)(1-i)/(1+i)(1-i)]^100

[(1+i²-2i)/(1²-i²)]^100

[(1-1-2i)/(1+1)]^100

(-2i/2)^100

(-i)^100

(-i²)^50

1^50=1


pal69: your ans is 1=1+0i
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