plz solve anyone
find a ND b
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[(1-i)(1-i)/(1+i)(1-i)]^100
[(1+i²-2i)/(1²-i²)]^100
[(1-1-2i)/(1+1)]^100
(-2i/2)^100
(-i)^100
(-i²)^50
1^50=1
pal69:
your ans is 1=1+0i
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