Question

plz solve as soon as possible ​

Answer 1

Answer:

Angle D = 50

Step-by-step explanation:

Sum of exterior angles of a quadrilateral = 360

3x+15+4x-5+2x-6+x+16 = 360

10x+20 = 360

10x = 360-20 = 340

x = 340/10 = 34

Angle A = 3x+15 = 102+15 = 117

Angle B = 4x-5 = 136-5 = 131

Angle C = 2x-6 = 68-6 = 62

Angle D = x+16 = 34+16 = 50

Answer 2

Answer:

49°

Step-by-step explanation:

Sum of all external angles of a quadrilateral =360

=> (x+16)°+(2x-6)°+(3x+15)°+(4x-5)°=360°

=> x+2x+3x+4x+16-6+15-5=360°

=> 10x+20=360°

=>10x= 340°

=>x=34°

So the given angles are

• x+16 = 50°
• 2x-6 = 62°
• 3x+15 = 117°
• 4x-5 = 131°

But we need to calculate the smallest angle of quad ABCD i.e. interior angles.

we know that, more the exterior angle the less will be interior angle

so, the max ext angle = 131°

hence, min int angle = 180-131 = 49° (linear pair)

PLS MARK IT BRAINLIEST!!!!