Question

plz solve asap
i will mark you as brainliest​

Answer 1

Answer:

Step-by-step explanation:

i) in ΔABC and ΔEDC

∠C=∠C                      {Common}

∠BAC=∠DEC            {AB║ED}

ΔABC≈ΔEDC            {AA similarity}

ii) BD/BC=1/3

 SO,

    DC/BC=2/3

 DC/BC=DE/AB      {BPT}

 2/3=DE/12.3

 DE=8.2 CM  

iii) areaΔEDC/areaΔABC=DE²/AB²

    areaΔEDC/areaΔABC=6724/15129