Plz solve, best ans will be marked as brainliest!! ABCD is a trapezium with AB||CD and angle BCD= twice the angle DAB. If DC=a and BC=b, find the length of AB.
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here is a similar answer I can solve it but . I had solved the similar question once so I copied it ok
By the figure BC=BE+CE
BE = x ( Parallel sides of parallelogram)
Angle B = 180–2z
in Triangle CDE
Angle E = B = 180–2z
Angle EDC = 180 - Angle E - Angle C
=> 180 - (180–2z) -z
=> 180 - 180 + 2z -z
Angle EDC = z
since in triangle CDE
Angle C = Angle D
then according to isosceles triangle i.e. ( sides opp. to equal angles are equal)
DE = EC
EC = x
Now BC = BE + EC
BC = y+ x
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Anonymous:
check bro am i right??
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