Question

plz solve brothers and sisters.
Really in need of ur help

Answer 1

$= > \frac{ {(p + \frac{1}{q} )}^{p} ( {p - \frac{1}{q}) }^{q} }{ {(q + \frac{1}{p}) }^{p} (q - \frac{1}{p} {)}^{q} } = {( \frac{p}{q}) }^{x} \\ \\ = > \frac{ {p}^{pq}( {1 + \frac{1}{pq}) }^{p}(1 - \frac{1}{pq} ) {}^{q} }{ {q}^{pq} {(1 + \frac{1}{pq} )}^{p}( {1 - \frac{1}{pq} )}^{q} } = (\frac{p}{q} ) {}^{x} \\ \\ = > {( \frac{p}{q}) }^{pq} = {( \frac{p}{q} )}^{x}$
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» By comparison :-

=> x = pq
________[ANSWER]

Your answer is option "4"