Question

plz solve class 9 maths...

Answer 1

2^a = 3^b= 6^c= k

2= k^(1/a)

3 = k^(1/b)

6= k^(1/c)


2× 3 = 6

k^(1/a) k^(1/b) = k^(1/c)

k^(1/a+ 1/b) = k^(1/c)

compare

1/a + 1/b = 1/c

b+a)/ab = 1/c

c= ab/(a+b)

Answer 2

$\huge\mathbb{Answer:-}$

$Let:-$

${2}^{a} = {3}^{b} = {6}^{c} = {k}$

$2 = {k}^{ \frac{1}{a} }$

$3 = {k}^{ \frac{1}{b} }$

$6 = {k}^{ \frac{1}{c} }$

$2 \times 3 = 6$

${k}^{ \frac{1}{a} } \times {k}^{ \frac{1}{b} } = {k}^{ \frac{1}{c} }$

${k}^{ \frac{1}{a} + \frac{1}{b} } = {k}^{ \frac{1}{c} }$

$\frac{1}{a} + \frac{1}{b} = \frac{1}{c}$

$\frac{a + b}{ab} = \frac{1}{c}$

$c = \frac{ab}{a + b}$

$<marquee>❤Shizu❤$