plz solve correctly ( If u don't know then don't solve!!!)
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Step-by-step explanation:
cos[3Π/2+x]cos(2Π+x) [cot{3Π/2-1}+cot(2Π+x)]
=(sinx cosx)[tanx+cotx]
=(sinx.cosx)[sinx/cosx+cosx/sinx]
=(sinxcosx)[1/sinxcosx]
=1
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