plz solve.........
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Answer:
x = -b and -a
Step-by-step explanation:
1/a + 1/b + 1/x = 1/(a + b + x)
1/a + 1/b = 1/(a + b + x) - 1/x
1/a + 1/b = (x - a - b - x)/(ax + bx + x²)
1/a + 1/b = (- a - b)/(x² + ax + bx)
(a + b)/ab = -(a +b)/(x² + ax + bx)
Cross-multiply it
-(a + b)(ab) = (x² + ax + bx)(a + b)
-(a + b)/(a + b) × (ab) = x² + ax + bx
-ab = x² + ax + bx
-ab = x² + x(a + b)
Factorise it
x² + x(a + b) + ab = 0
x² + ax + bx + ab = 0
Take common
x(x + a) + b(x + a) = 0
(x + b)(x + a) = 0
On comparing we get,
x = -b, -a
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