Question

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Answer 1

√3x² - 8x + 4√3

= √3x² - 6x - 2x + 4√3

= √3x² - 2√3√3x - 2x + 4√3

= √3x(x - 2√3) - 2(x - 2√3)

= (√3x - 2)(x - 2√3)

√3x - 2 = 0 or x - 2√3 = 0

x = 2/√3 or x = 2√3

Answer 2

Answer:

The zeroes are $2\sqrt{3}\ and\ \frac{2}{\sqrt{3}}$.

Step-by-step explanation:

Factorize the expression as follows:

$\sqrt{3}x^{2}-8x+4\sqrt{3}=0\\\sqrt{3}x^{2}-6x-2x+4\sqrt{3}=0\\\sqrt{3}x(x-2\sqrt{3})-2(x-2\sqrt{3})=0\\(x-2\sqrt{3})(\sqrt{3}x-2)=0$

If $(x-2\sqrt{3})=0$ then the value of x is,

$x-2\sqrt{3}=0\\x=2\sqrt{3}$

If $(\sqrt{3}x-2)=0$ then the value of x is,

$\sqrt{3}x-2=0\\x=\frac{2}{\sqrt{3}}$

Thus, the zeroes are $2\sqrt{3}\ and\ \frac{2}{\sqrt{3}}$.