Question

plz solve fast people​

Answer 1

SOLUTION

$= > 4 \sqrt{3} {x}^{2} + 5x - 2 \sqrt{3} = 0 \\ = > 4 \sqrt{3} {x}^{2} + 8x - 3x - 2 \sqrt{3} = 0 \\ = > 4x( \sqrt{3} x + 2) - \sqrt{3} ( \sqrt{3} x + 2) = 0 \\ = > ( \sqrt{3} x + 2) \: (4x - \sqrt{ 3} ) = 0 \\ = > ( \sqrt{3} x + 2) = 0 \: \: or \: \: (4x - \sqrt{3} ) = 0 \\ = > x = - \frac{2}{ \sqrt{3} } \: \: or \: \: x = \frac{ \sqrt{3} }{4}$

Now,

Sum of zeroes = -b/a = -5/4√3

Also sum of zeroes = √3/4+(-2/√3)

=) Sum = 3-8/4√3

=) -5/4√3 Hence verified that actual sum = -b/a

Now, Product of zeroes = c/a = -2√3/4√3= -1/2

Also product of zeroes =(√3/4)× (-2/√3)

=) -2/4 = -1/2

Hence verified that actual product= c/a

hope it helps ☺️