Question

Plz solve fast plz....

Both parts.. Plz.. ​

Answer 1

Step-by-step explanation:

hope it is helpful to you

Answer 2

Hii its tom85

tan^-1(1/(2x+1 ) + 1/(4x+1))/1 - 1/(2x+1)(4x+1) = tan^-12/x^2

6x+2/(-1 + 8x^2 + 6x +1 ) = 2/ x^2

2(3x +1)/2x(4x +3) = 2/x^2

3x^2 +x = +8x +6

3x^2 - 7x - 6= 0

3x^2 - 7x - 6 = 0

3X^2 - 9x +2x -6 = 0

(3x+2 )( x- 3)= 0

x= -2/3 and 3

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hope it may helps you