Question

plz solve fast

Ques no 31...​

Answer 1

hey due hope this helps you..,

Step-by-step explanation:

Given In ΔABC, ∠A = 90° and AL ⊥ BC

To prove ∠BAL = ∠ACB

PROOF:

In ΔABC and ΔLAC,

∠BAC = ∠ALC [each 90°] …(i)

and ∠ABC = ∠ABL [common angle] …(ii)

On adding Eqs. (i) and (ii),

we get;

∠BAC + ∠ABC = ∠ALC + ∠ABL …(iii)

Again, in ΔABC,

∠BAC + ∠ACB + ∠ABC = 180°

[sum of all angles of a triangle is 180°]

⇒∠BAC+∠ABC = 1 80°-∠ACB …(iv)

In ΔABL,

∠ABL + ∠ALB + ∠BAL = 180°

[sum of all angles of a triangle is 180°]

⇒ ∠ABL+ ∠ALC = 180° – ∠BAL [∴ ∠ALC = ∠ALB= 90°] …(v)

On substituting the value from Eqs. (iv) and (v) in. Eq. (iii),

we get ,

180° – ∠ACS = 180° – ∠SAL

⇒ ∠ACB = ∠BAL

Hence proved.

Answer 2

Ello ✌️

here is ur answer....

in the attachment !

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