Question

plz solve fast step by step

Answer 1

Given Equation is 2ax + 3by - a - 2b = 0   ------ (1)

a1 = 2a, b1 = 3b, c1 = -a - 2b

Given Equation is 3ax + 2by - 2a - b = 0    ------ (2)

a2 = 3a, b2 = 2b, c2 = -2a - b.

Now,

We need to calculate the x and y using cross-multiplication method.

$\frac{x}{b1c2 - b2c1} = \frac{y}{c1a2 - c2a1} = \frac{1}{a1b2 - a2b1}$

$\frac{x}{3b(-2a-b) - 2b(-a-2b)} = \frac{y}{3a(-a-2b) - 2a(-2a-b)} = \frac{1}{2a*2b-3a*3b}$


$\frac{x}{-6ab - 3b^2 + 2ab + 4b^2} = \frac{y}{-3a^2 - 6ab +4a^2 + 2ab} = \frac{1}{4ab - 9ab}$


$\frac{x}{b^2 - 4ab} = \frac{y}{a^2 - 4ab} = \frac{1}{-5ab}$


Now,

$\frac{x}{b^2 - 4ab} = \frac{1}{-5ab}$

$x = \frac{b^2 - 4ab}{-5ab}$

$x = \frac{-b(4a - b)}{-b(5a)}$

$x = \frac{4a - b}{5a}$



Now,

$\frac{y}{a^2 - 4ab} = \frac{1}{-5ab}$

$y = \frac{a^2 - 4ab}{-5ab}$

$y = \frac{-a(4b - a)}{-a(5b)}$

$y = \frac{4b - a}{5b}$



Hope this helps!

Answer 2

Hi,

Please see the attached file!



Thanks