Question

plz solve fast with explain q no 13

Answer 1

{tan2¢+sin2¢+2tan¢sin¢}-(tan2¢+s

in2¢-2tan¢sin¢}

=4tan¢sin¢

And

4√{tan2¢-sin2¢}=4√{sin2¢÷cos2¢-sin2¢}

=4(sin¢÷cos¢)(√1-cos2¢)

=4tan¢sin¢