Question

Plz solve fastly.Spam answer will be reported. I'll mark as BRAINLIEST ​

Answer 1

Solution :

-r² + p² + q² - 2pq

=> -r² + [ p² + q² - 2pq ]

=> -r² + [ p² - 2pq + q² ]

=> -r² + ( p - q )²

=> ( p - q )² - r²

=> [p - q + r ][ p - q - r ]

=> [ p - q - r ][ p - q + r]

Hence , Option A is the correct answer .

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Additional Information -

(a + b)² = a² + 2ab + b²

(a + b)² = (a - b)² + 4ab

(a - b)² = a² - 2ab + b²

(a - b)² = (a + b)² - 4ab

a² + b² = (a + b)² - 2ab

a² + b² = (a - b)² + 2ab

2 (a² + b²) = (a + b)² + (a - b)²

4ab = (a + b)² - (a - b)²

ab = {(a + b)/2}² - {(a-b)/2}²

(a + b + c)² = a² + b² + c² + 2(ab + bc + ca)

(a + b)³ = a³ + 3a²b + 3ab² b³

(a + b)³ = a³ + b³ + 3ab(a + b)

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)( a² - ab + b² )

a³ + b³ = (a + b)³ - 3ab( a + b)

a³ - b³ = (a - b)( a² + ab + b²)

a³ - b³ = (a - b)³ + 3ab ( a - b )

______________________________

Answer 2

Given Question

Factorize The Polynomial - r² + p² + q² - 2pq

SoluTion

= - r² + p² + q² - 2pq

= - r² + [ p² + q² - 2pq ]

= - r² + [ p² - 2pq + q² ]

= -r² + [ p - q ]²

= [ p - q ]² - r²

= [ p - q - r ] [ p - q + r ]

Hence, Option A is Right :)

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