plz solve how to solve this ques. its really urgent.......
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here is the answer of your question
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See first let solve the question
first(3+2root5)2= (3)^2 + (2root5)^2 + 2(3)(2root5)= 9 + 10 + 12root5 = 19 + 12root5 so let us now first take it as rational no.means it will be equal to p/q where q is not equal to 0 so 19 + 12root5 = p/q 12root5 = p/q - 19 since rational no. subtracted from a rational no. gives rational no. so 12root5 should be rational but since any rational multiplied but irrational no.(root5) gives irrational no.so there is a contradiction and hence(3+2root5)^2is irrational no.
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first(3+2root5)2= (3)^2 + (2root5)^2 + 2(3)(2root5)= 9 + 10 + 12root5 = 19 + 12root5 so let us now first take it as rational no.means it will be equal to p/q where q is not equal to 0 so 19 + 12root5 = p/q 12root5 = p/q - 19 since rational no. subtracted from a rational no. gives rational no. so 12root5 should be rational but since any rational multiplied but irrational no.(root5) gives irrational no.so there is a contradiction and hence(3+2root5)^2is irrational no.
If my answer suits you so plzzzzzzzzzz give me Thanks and mark it as brainliest.
dhruvparashar875:
ok okkk
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