Question

plz solve
I and my father tried but could not solve ​

Answer 1

Step-by-step explanation:

$\huge\begin{lgathered}\frak\red{answEr}\end{lgathered}$

let the 3 angles be 'x' , 'x+10' , 'x+20'

$\huge\mathfrak\blue{applying\: conditions}$

====> x+x+10+x+20 = 2 right angles

right angle = 90°

====> 2 right angle = 2×90 = 180°

====> 3x + 30 = 180

====> x+10 = 60

====> x = 50°

since , x was the smallest angle,,

the answer becomes 50°

hope this helps

♥️♥️@jtg07♥️♥️

Answer 2

Answer:

The smallest angle = 50°

Step-by-step explanation:

Let the smallest angle is x

By the given condition they differ by 10° between two pairs

So 2nd angle = (x+10°)

Also the last one must also differ by 10°

so it will be (x+10°+10°) = (x+20°)

)We know that sum of all three angles is 180°

So

x+(x+10°)+(x+20°)=180°

x+x+10°+x+20°=180°

3x+30°=180°

3x=180° - 30°

3x=150°

x=150°/3

/3x=50°

Therefore smallest angle = 50°