Question

Plz solve in detail...

Answer 1

Heya

(2) a^log n to the base a is n

x^log (1-x)² to the base x is (1-x)²

(1-x)²= 9

1-x = √9

1-x=+/-3

x= 4

x= -2

Option 1.

(3) nloga = log a^n

logx+log = log xy

log2+log√a + log √b = log(a+b)

log 2√ab = log (a+b)

2√ab = a+b

√a²+√b²-2√ab = 0

(√a - √b)²= 0

√a-√b= 0

√a=√b

=> a=b

Hope it helps!

(Sorry I have no idea about the first one)