plz solve in ur own handwriting class9 chemistry ques 11
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let the % of B10 is = X
Hence other B11 is = 1-x
by formula
(B10 mass).x + (B11 mass)(1-x) = average mass
hence
10x + 11(1-x) = 10.8
10x + 11-11x = 10.8
-x = 10.8 - 11= -0.2
x = 0.2
& 1-x = 0.8
hence B10 % = 0.2×100 = 20%
and B11 % = 0.8×100 = 80%
Hence other B11 is = 1-x
by formula
(B10 mass).x + (B11 mass)(1-x) = average mass
hence
10x + 11(1-x) = 10.8
10x + 11-11x = 10.8
-x = 10.8 - 11= -0.2
x = 0.2
& 1-x = 0.8
hence B10 % = 0.2×100 = 20%
and B11 % = 0.8×100 = 80%
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