Math, asked by rajivsinhacbsa, 8 months ago

plz solve it ..............​

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Answered by pritambehera2004
0

(a^2+b^2)(a^2+b^2)-(a^2-b^2)(a^2-b^2)

=(a^2+b^2)^2-(a^2-b^2)^2

=[(a^2)^2+(b^2)^2+2*(a^2)*(b^2)]-[(a^2)^2+(b^2)^2-2*(a^2)*(b^2)

=a^4+b^4+2a^2b^2-a^4-b^4+2a^2b^2

=4a^2b^2

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