Question

plz solve it .......
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Answer 1

this is it

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Answer 2

in triangles DEN and DFM

angleD = angle D    common

DE=DF        given

angle DNE = angle DMF

so  triangle DEN is congruent to DFM by ASA criteria

by CPCT  

DM= DN

now in triangles EMF and FNE

angle M = angle M = 90        given

EM = FN             as DM = DN and DE = DF by subtracting them we get EM = FN

EF = EF                     common

by RHS criteria triangle EMF is congruent to FNE

by CPCT

FM = EN

EM = FM

hence proved

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