Question

Plz solve it ! AFAP !​

Answer 1

Question :

A shell of mass 4kg at rest explodes into two parts with masses in ratio 1:2. The velocity of lighter part after explosion is (2i + 3j) m/s. Find the velocity of the other part.

Solution :

Let mass of lighter part be 1x and mass of heavier part be 2x.

❖ Since no external force acts on the shell linear momentum is conserved.

Hence total momentum before explosion will be equal to the total momentum after explosion.

$\sf:\implies\:Initial\: momentum=Final\: momentum$

$\sf:\implies\:Mu=m_1v_1+m_2v_2$

• M denotes mass of shell
• u denotes initial velocity of shell before explosion
• m₁ and m₂ denotes masses of lighter and heavier parts respectively
• v₁ and v₂ denotes final velocities of lighter and heavier parts respectively after explosion

By substituting the given values,

$\sf:\implies\:(4)(0)=1x(2\hat{i}+3\hat{j})+2x\cdot v_2$

$\sf:\implies\:2x\cdot v_2=-1x(2\hat i+3\hat j)$

$\sf:\implies\:v_2=-\dfrac{1}{2}(2\hat i+3\hat j)$

$:\implies\:\underline{\boxed{\bf{\orange{v_2=\left(-\hat i-\dfrac{3}{2}\hat j\right)\:ms^{-1}}}}}$

Answer 2

Answer:

Hope you are having a good day ✌