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Question :
A shell of mass 4kg at rest explodes into two parts with masses in ratio 1:2. The velocity of lighter part after explosion is (2i + 3j) m/s. Find the velocity of the other part.
Solution :
Let mass of lighter part be 1x and mass of heavier part be 2x.
❖ Since no external force acts on the shell linear momentum is conserved.
Hence total momentum before explosion will be equal to the total momentum after explosion.
- M denotes mass of shell
- u denotes initial velocity of shell before explosion
- m₁ and m₂ denotes masses of lighter and heavier parts respectively
- v₁ and v₂ denotes final velocities of lighter and heavier parts respectively after explosion
By substituting the given values,
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