Question

plz solve it as soon as possible ​

Answer 1

Answer:

investment ( principal ) = 20,000

time ( n ) = 3 years

rate ( i ) = 10 %

i = 10/100 = 0.1

a. the interest he earns for the first year

=

$p(1 + i) ^{n} - p$

= 20,000 ( 1 + 0.1 )¹ - 20,000

= 20,000 ( 1.1 ) ¹ - 20,00

= 22,000 - 20,000

= 2,000

b. the sum due to ramesh at the end of 2nd year

= 20,000 (1.1)² - 20,000

= 20,000 ( 1.21 ) - 20,000

= 24,200 - 20,000

= 4,200

c. the total amount due at the end of 3rd year

= 20,000 ( 1.1 )³ - 20,000

= 20,000 ( 1.331 ) - 20,000

= 26,620 - 20,000

= 6,620

hope this is helpful

Answer 2

Answer:

a . 200

b.400

c.2600

Step-by-step explanation:

a. 2000 X 10/100 X 1= 200

b.2000 X 10/100 X 2 =400

c. 2000X10/100X 3=2600

2000+600=2600